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iogann1982 [59]
2 years ago
11

Based upon historical data, it is known that 8% of 12-egg cartons contain at least one broken egg. A grocery store manager would

like to carry out a simulation to estimate the number of cartons, in a sample of 10, that would contain at least one broken egg. She assigns the digits to the outcomes.
01-08 = carton contains a broken egg
09-99, 00 = carton does not contain a broken egg
Here is a portion of a random number table.
1 31645 03495 96193 10898
2 67940 85019 98036 98252
3 21805 26727 73239 53929
4 03648 93116 98590 10083
5 71716 46584 35453 98153
In the first trial, line 1, 1 of the first 10 double-digit numbers is between 01 and 08, meaning that 1 of the 10 cartons of eggs contains at least one broken egg. Starting at line 2 and using a new line for each trial, carry out 4 more trials. Based on the 5 trials, how many cartons of eggs out of 10 cartons are expected to contain at least one broken egg, on average?
A. 0
B. 1
C. 2
D. 8
Mathematics
1 answer:
kakasveta [241]2 years ago
4 0

Based on the 5 trials, 1 carton of eggs is expected to contain at least one broken egg, on average

<h3>How to determine the number of cartons</h3>

From the question, we understand that only one of the first 10 double-digit numbers is between 01 and 08

This means that:

The average carton or the expected value of eggs in the simulation is 1

Hence, 1 carton of eggs is expected to contain at least one broken egg, on average

Read more about expected values at:

brainly.com/question/15858152

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Since n = numbers of bars purchase.

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Therefore, to find the numbers of bars that the team would need to purchase from each company in order for the total cost to be equal =

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