Answer:
6 seconds
Step-by-step explanation:
<u><em>The question in English is</em></u>
An object is thrown from a platform.
Its height (in meters), x seconds after launch, is modeled by:
h(x)=-5x^2+20x+60
How many seconds after the launch does the object reach the ground?
Let
x ----> the time in seconds
h(x) ---> the height of the object
we have

we know that
When the object hit the ground the height is equal to zero
so
For h(x)=0
we have

The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
The solution is x=6 sec
The he object reach the ground at x=6 seconds
First of all, you have to define the value which cannot be changed, in this case it is $250, becuase it is a fixed fee.Then subtract 250 the fee from the amout of money that school can spend = 335
Then divide remaining cash by 8 the price per student : 335:8
and you will get 41.875
As you can see, you have to round the number down to 41, otherwise we would go over the school budget.
Therefore, the number of students is 41.
Sure. what is it that you have to do with statistics
Answer:
A) -1/3
Step-by-step explanation:
y = mx + b
m = slope
b = y-intercept
y = -1/3x + 2
m = -1/3
Step-by-step explanation:
x+3x+90=360
4x=360-90
x=270/4
x=67.5