Answer:
1. the set of real numbers between 0.1 and 0.2
2. the set of all negative integers greater than negative 1 trillion
3. the set of all java and C programs
Explanation:
A set is countable if it is either finite or has the same cardinality as the set of positive integers. The inverse of this set type is uncountable.
The set of real numbers between 0.1 and 0.2, all negative integers greater than negative 1 billion, and a set of java and C programs are all countable sets, so are considered countably infinite.
Answer:
Please find the 3 options below.
Explanation:
To begin with, Task Manager in windows, is a monitor program that provides information or shows application and processes running on a computer. Task manager also provide insights about the general status of a computer. The three options for entering or accessing task manager in windows are:
1. Press Ctrl+Alt+Delete and then click Task Manager
2. Right-click the taskbar and choose Start Task Manager
3. Right-click the taskbar and choose Manage Tasks
Answer:
Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.
;Include Irvine32.inc file used with link library for 32 bit applications
.386
.model flat,stdcall
.stack 4096
ExitProcess proto,dwExitCode:dword
INCLUDE Irvine32.inc
.data
myArray DWORD 0,2,5,9,10
arrSize = ($-myArray)/TYPE myArray
gapArr DWORD arrSize-1 DUP(?)
sum DWORD ?
.code
main PROC
;Call the procedure
call Clrscr
;Initialize ESI pointer
mov esi, 0
mov ecx, arrSize
dec ecx
L1:
mov eax, myArray[esi+4]
sub eax, myArray[esi]
mov gapArr[esi], eax
inc esi
loop L1
;Calculate the sum of gaps between array elements
mov sum, 0
mov esi, 0
mov ecx, arrSize
dec ecx
; move gapArr[esi] to a temporary register and then add that register value to sum
L2:
mov edx, gapArr[esi]
add sum, edx
inc esi
loop L2
INVOKE ExitProcess,0
main ENDP
END main
Explanation:
Answer:
Please see the attachment for the solution
Explanation:
