4 years ago

Multiply 5 x 23 x 2=

Mathematics

1 answer:

Masja [62]4 years ago

7 0

5 x 23 x 2 = 230.
hope this helped!!

You might be interested in

Evaluate the expression when a= 2 and c=-4.<br> -a +5c

-Dominant- [34]

The answer would be 18

4 0

3 years ago

Find the product. 1/8 times 8 to the square root

Nastasia [14]

Step-by-step explanation:

The product 1/8 times 8 to the square root

3 0

3 years ago

Read 2 more answers

I need help plzzzzzzzzzzzzjdbfhrrhebehdbzzzzzzzzzzzzzzzz

yulyashka [42]

Answer:A

Step-by-step explanation: im not too sure but i think 1-2/5=3/5 which would be red so

4 0

3 years ago

Read 2 more answers

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

A planer is set to remove 1/16 inch from a board on each pass. If the board starts out at 3/4 inch thick how many passes would y

Pachacha [2.7K]

The answer would be 7 passes

7 0

3 years ago

Read 2 more answers