Answer:
3
Step-by-step explanation:
these are 2 similar triangles (all 3 pairs of corresponding angles are equal in their pair, and the lengths of corresponding sides have the same ratio in every pair of corresponding sides and other lengths).
and they are also right-angled triangles.
so, what else do we know about them ?
PQ = 18
RT = 6
ST = QT + 9
therefore
QT = ST - 9
and
QR = QT + RT = ST - 9 + 6 = ST - 3
due to the principles of cumulative triangles
PQ/ST = QR/RT = 18/ST = (ST - 3)/6
108/ST = (ST - 3)
108 = (ST - 3)ST = ST² - 3ST
ST² - 3ST - 108 = 0
we can the write
x² - 3x - 108 = 0
and the solution for such a squared equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = -3
c = -108
x = (3 ± sqrt(9 - 4×1×-108))/2 = (3 ± sqrt(441))/2 =
= (3 ± 21)/2
x1 = (3+21)/2 = 24/2 = 12
x2 = (3-21)/2 = -18/2 = -9
a negative solution for real lengths is not valid, so we know
x = ST = 12
so,
QR = ST - 3 = 12 - 3 = 9
and then
QT = QR - RT = 9 - 6 = 3
<h2>Answer:</h2>
B. {10, 20, 30, 40, 50, 60, 70}
<h2>Explanation:</h2>
- The domain of a function is defined as the set of all input values. Or in other words the set of all first element of ordered pairs.
In the given input-output table, the set of all input values will be the domain of the given function.
Answer: yes they are the same
Answer:
12 - x
Step-by-step explanation:
y = -x + 12
Replace x with y.
x = -y + 12
Solve for y, x = -y + 12
= 12 - x
Hope this helps, please mark brainliest if possible. :)
I don’t see a picture so please put a picture :D
