Answer:
Step-by-step explanation:
y=x²-2x-1
and y=-3x+5
x²-2x-1=-3x+5
x²+x-6=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x=-3,2
when x=-3
y=-3×-3+5=9+5=14
when x=2
y=-3×2+5=-6+5=-1
so solutions are (-3,14) and (2,-1)
Recall your d = rt, distance = rate * time.
as the plane goes against the wind, the plane is not really flying at "x" mph, but is really going slower, at " x - y ", because the wind is subtracting speed from it.
likewise, when the plane is going with the wind, is not really going at "x" mph, but at " x + y ", is going faster due to the wind, thus
Answer:2
Step-by-step explanation: 5 - 3 = 2
Where R is the median between Q and L:
From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.
NS = 2SR
(x + 10) = 2(x + 3)
x + 10 = 2x + 6
x = 4
Therefore, SR = (x + 3) = 7