Answer: 12.8
Step-by-step explanation:
Divide 80.5 by pi then divide by 2
It would still be 13.6 because the 0 does not change anything.
Answer:
A: ![\frac{1}{2\sqrt{x-1} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx-1%7D%20%7D)
B:![\frac{1}{4\sqrt[4]{x^{3} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Csqrt%5B4%5D%7Bx%5E%7B3%7D%20%7D%20%7D)
c: 2x
Step-by-step explanation:
To find the derivative of x raised to the nth power we use the following template
Something else to keep in mind is that
![\sqrt[n]{x^{y}}=x^{y/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7By%7D%7D%3Dx%5E%7By%2Fn%7D)
So knowing this we can rewrite a as follows
![\sqrt{x-1} =(x-1)^{1/2}](https://tex.z-dn.net/?f=%5Csqrt%7Bx-1%7D%20%3D%28x-1%29%5E%7B1%2F2%7D)
so we can use the template above and get
![\frac{1}{2}(x-1)^{.5-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28x-1%29%5E%7B.5-1%7D)
So that simplifies to
![\frac{1}{2}*(x-1)^{-\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2A%28x-1%29%5E%7B-%5Cfrac%7B1%7D%7B2%7D)
![\frac{(x-1)^{-.5}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x-1%29%5E%7B-.5%7D%7D%7B2%7D)
![\frac{1}{2\sqrt{x-1} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx-1%7D%20%7D)
B: Same kind of deal here
![\sqrt[4]{x}=x^{\frac{1}{4} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D)
![\frac{1}{4} *x^{\frac{1}{4}-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%2Ax%5E%7B%5Cfrac%7B1%7D%7B4%7D-1%7D)
![\frac{x^{-\frac{3}{4}}}{4} =\frac{1}{4\sqrt[4]{x^{3} } }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B-%5Cfrac%7B3%7D%7B4%7D%7D%7D%7B4%7D%20%3D%5Cfrac%7B1%7D%7B4%5Csqrt%5B4%5D%7Bx%5E%7B3%7D%20%7D%20%7D)
C: this one is by far the easiest because the derivative of a constant is 0 so we can just apply the same template from before and get
2x
That would be 0.272727272727272727
In fraction form = 3/11