Using S = ut + 1/2gt², from rest, u = 0
S = 1/2gt², g ≈ 9.8 m/s²
S = <span>1/2 *9.8*3²
</span>S = 0.5<span> *9.8*3*3
</span>
<span>S ≈ 44.1 m</span>
Answer:no
Step-by-step explanation:
Answer:
(7/15,−13/5)
Equation Form:
x=7/15,y=−13/5
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
It’s b here is proof of what i got
