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slava [35]
3 years ago
15

Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Da

kota's ages is 93. What is Susanne's age?
Mathematics
1 answer:
belka [17]3 years ago
5 0
Susanne is 16 years old.

b = Bob's age

s = Susanne's age

d = Dakota's age

Bob's age is 4 times greater than Susanne's age:

b = 4s

Dakota is three years younger than Susanne:

d = s - 3

The sum of Bob's, Susanne's, and Dakota's ages is 93:

b + s + d = 93


 solve these equations:

b = 4s

d = s - 3

b + s + d = 93


and get:

b = 64 years

s = 16 years

(remember that s = Susanne) 

d = 13 years
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Answer:

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Step-by-step explanation:

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1.
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2. 

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6 0
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salesperson at a furniture store earns a 3% commission on all sales. How much commission does the salesperson earn on a $1400 sa
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3 0
3 years ago
A competition to catch the most rainbow trout on Lake Rainbow pitched the men against the ladies. 16 men and 12 women participat
Valentin [98]

The probability that a participant successfully catches 3 rainbow trout, given that the participant was a woman is 0.0042.

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= 3/7

P(men) = 16/28

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= P(3 trout | women)*(3/7) + (15C3 * (0.09^3)*(1-0.09)^(15*3))*(4/7)

= P(3 trout | women)*(3/7) + (0.00476)*(4/7)

P(woman | 3 trout) = P(3 trout | women)*P(woman) / P(3 trouts)

{P(3 trout | women) = p}

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p*(3/7)/0.40 = (p*(3/7) + (0.00476)*(4/7))

p*((3/7)/0.40 - (3/7)) = (0.00476)*(4/7)

p = [(0.00476)*(4/7)] / [((3/7)/0.40 - (3/7))]

= 0.0042

Learn more about probability here brainly.com/question/24756209

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7 0
2 years ago
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