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Andrej [43]
3 years ago
13

Use the information provided to write the equation of each parabola in vertex form and intercept form.

Mathematics
1 answer:
igomit [66]3 years ago
8 0
I think it’s B
Hopefully this helps!!
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Which are possible lengths of the sides for a triangle?
icang [17]

Answer:

D

Step-by-step explanation:

im not sure if they can be the same length, but heres the explanation: so a+b is higher than c, (9=a, 7=b, 11=c) but c is the bigger number by itself. so since a+b is higher added together, it makes it a triangle. sorry if this is wrong but i think its right.

4 0
3 years ago
38.7÷1.29 help I'm stuck
Darya [45]

1.29 can go into 38.7 30 times, Your answer is 30.

5 0
3 years ago
Read 2 more answers
Distance traveled varies jointly as rate and time. If Fred travels 135 miles in 3 hours at a rate of 45 mi/hr, find the rate at
Rudiy27

From the relation, d is joint proportionaly with r and t.
Thus,d = krt.

Using the first set of given, we could calculate for k.135 = k(45)(3)k = 1

Using the computed value of k.d = krtr = d/ktr = (189)/(1)(3.5) = 54 mph.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
Hii pls help i’ll give brainliest if you give a correct answer
allochka39001 [22]

Answer:

A

Step-by-step explanation:

The Moon actually takes 27.3 days to complete one orbit around Earth

5 0
3 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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