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natima [27]
2 years ago
7

Tell whether the angles are complementary, supplementary, or neither.

Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

Answer:they are supplementary

Step-by-step explanation:

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3 years ago
"Two planes leave the airport at the same time. Plane 1 travels just 9 miles east from
Vika [28.1K]
The answer is 41 miles


Imagine the diagonal distance is called c
Using Pythagorean theorem 40^2 + 9^2 = c^2
1600 + 81 = c^2
The square root of 1681 is 41
So c = 41
8 0
3 years ago
4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
8 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
4 years ago
Tickets to a hockey game cost $35 each. What is the total cost for 5 tickets?
nordsb [41]

The answer would be $175

Multiply the most by the number of tickets

5 0
2 years ago
Read 2 more answers
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