Tell whether the angles are complementary, supplementary, or neither.

Which equation represents each scenario

Mkey [24]

Answer:

if she question 1 spend $25 out of the $150, then you would do 150 sub 25 to get 125

Kevin has 10 signs. he's adding 5 signs, so divide 10 to 5 to get 2

Harvey has 5 in 1 minute, i would say in 2 minutes he'll have 10

Fran adds $25 to her $150 then she'll get $175.

Step-by-step explanation:

P= Parentheses

E= Exponent

M= Multiplication

D= Division

A= Addition

S= Subtraction

If this doesn't help then sorry , hope this helps.

4 0

2 years ago

The distance from the school to the library is 12 miles. The distance from the school to the park is 75% of this distance.

strojnjashka [21]

75% of 12 can be represented with the equation 75/100=x/12

Then to solve
75(12)= 100x
900 = 100x
9=x

So the distance from the school to the park is 9 miles.

8 0

3 years ago

Read 2 more answers

What is the area of the triangle? please helpppp

Ilya [14]

Where is the picture of the triangle?

5 0

3 years ago

Read 2 more answers

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

F = The word free occurs in an email

S = The email is spam

V = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

3 years ago

Find the area of the parallelogram

matrenka [14]

Answer:

45 m

Step-by-step explanation:

Here,

Base (b) = 9m

Height (h) = 5m

Area of parallelogram = b * h. = 9*5. = 45m

3 0

3 years ago