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Sladkaya [172]
3 years ago
11

I need help on this if anyone can help

Mathematics
1 answer:
olga55 [171]3 years ago
6 0
Isn’t it side-angle-side
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A glitter glue recipe takes a mixture of 1 5 cup of glitter to 2 5 cup of glue. For A, how many cups of glitter are used for 1 c
tatiyna

0.6 cup of gliter is used for 1 cup of glue and 1.6 cup of gliter glue is made with 1 cup of glue.

Part A

Given that,

15 cup of gliter is for 25 cup of glue ,

Therefore, "X" cup of gliter is for 1 cup of glue

X = (1*15)/25

X= 0.6 cup of gliter

Part B,

Given that,

From part A 0.6 cup of gliter is for 1 cup of glue

Thus, 1 cup of glue and 0.6 cup of gliter when mixed will form "Y" cup of gliter glue

Now, Y= 0.6 cup of gliter + 1 cup of glue

Y= 1.6 cup of gliter glue

which approximates to 2 cup of gliter glue.

For more information on cross multiplication kindly visit to

brainly.com/question/11203238

3 0
1 year ago
A line with a slope of –1 passes through the point (–10, 0). What
slega [8]

Answer:

y= -x - 10

Step-by-step explanation:

provided in photo

4 0
3 years ago
Kevin and randy muise have a jar containing 68 ​coins, all of which are either quarters or nickels. the total value of the coins
Monica [59]
For this case, the first thing we must do is define variables:
 x: number of quarters
 y: number of nickels
 We now write the system of equations:
 x + y = 68
 0.25x + 0.05y = 13.40
 Solving the system we have:
 x = 50
 y = 18
 Answer:
 
they have:
 
quarters = 50
 
nickels = 18
3 0
3 years ago
What is -4+0+y, When y=16
BlackZzzverrR [31]

\large \mathfrak{Solution : }

let's plug in the value of y :

  • -4 + 0 + y

  • -4 + 16

  • 12
8 0
3 years ago
Read 2 more answers
Find the distance between the points with coordinates (5, 7) and (-3, 1)
Bess [88]
You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.

Now plug in your numbers.

This gives you root(7-1)^2+(5-(-3))^2.

Simplify to root(6)^2+(8)^2. Simplify again to root36+64.

Simplify one more time to root 100. now solve.

Your answer is 10.
7 0
3 years ago
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