Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=
for x²-4x+16=0
x=
x=
x=
x=
x=
x=
the roots are
x=-4 and 2+2i√3 and 2-2i√3
Mm dont know but keep trying
That's a copy of the figure from the other post; I didn't look at the answer.
We have Start(0,0)
Your team takes the direct path at a constant speed of 6 miles per hour.
<span>Our team.
</span><span>
Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.
Team Blue follows the riddle and travels at a constant speed of 10 mph.
</span>
<span>
Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.</span>
Winner: our team, then Blue, then Red, then Yellow
<span>
</span>
Answer:
The procedure for this case is add three, then divide by 5.
Step-by-step explanation:
if y=5x-3
to find the inverse, we exchange x and y then solve for the new y.
x=5y-3 add 3
x+3 = 5y divide by 5
(x+3)/5 = y
or
inverse, y=(x+3)/5
The procedure for this case is add three, then divide by 5.
