First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
The graph represented in the figure shows a set of linear equations each of which is represented a straight line.
Step-by-step explanation:
System of Equation can be referred to as an assortment of equations to be dealt with. Common examples include linear equations and non-linear equations such as a parabola, hyperbola etc.
Linear set of equations are the most simple of equation depicting a linear relationship between two variables.
E.g. Y=4x+3
here y and x share a linear relationship which is defined by the straight-line graph "4x+3"
Similarly in the graph lines, two straight lines are depicted which symbolises that the et of the equation is linear in character.
Well the equation is (A^2)+(B^2)=(C^2)
A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25
So if you plug in those numbers into the equation...
(x^2) + (2x^2) = (25^2)
x^2 + 4x^2 = 625
Combine like terms
5x^2 = 625
Divide by five to both sides
x^2 = 125
Then Square root,
x = sqrt(125)
x = sqrt(25* 5)
x = 5sqrt(5)
Answer:
1. coefficient
2. variable
3. constant
Step-by-step explanation: