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Tamiku [17]
3 years ago
10

What is the slope line perpendicular to the equation 4x+3y=9

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

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Gemiola [76]

Hi!

I'm not sure how to slove this, but I do know how to solve it ;D

<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>

\frac{x+y}{z*z}=3*z

x + y = 3 * z

<h3>Now subtract x from both sides.</h3>

x - x + y = 3 * z - x

<u>y = 3 * z - x</u>

<h2>The answer is y = 3 * z - x</h2>

Hope this helps! :)

-Peredhel

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<em></em>

Step-by-step explanation:

Given

The attached graph

Required

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