Check the picture below.
keeping in mind that a cube is just a rectangular prism with all equal sides.
Answer:
\left(ax^2\right)\left(-6x^b\right)=12x^5\\\\(-6a)x^{2+b}=12x^5\to -6a=12\ and\ 2+b=5\\\\-6a=12\ \ \ |:(-6)\\a=-2\\\\2+b=5\ \ \ |-2\\b=3
Answer:\ a=-2;\ b=3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Note that this function is not defined at x = 0; it does have a vertical asymptote which is the line x = 0, as well as a horiz. asymptote which is the line y = 0. This function is odd because the power of x is -1 (a negative odd number). Half the graph appears in Quadrant I: (1, 1), (2, 1/2), (3, 1/3), etc.
The other half is the reflection of the Quadrant I part in the origin, and this is because the function is odd.
Answer:
It should be -5/2 for the points (-6,8) (-16,33)
Step-by-step explanation:
Answer:
4394
5200 X 0.12 = 624 --> 5200 - 624 = 4576
5200 X 0.035 = 182
4576 - 182 = 4394
