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suter [353]
3 years ago
13

Answer fast pleaseee, Solve the following system of equations: y= -5x +1 and y= -x-3

Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer:

x=1 y=-4

Step-by-step explanation:

USPshnik [31]3 years ago
5 0

Answer:

(1, - 4 )

Step-by-step explanation:

Given the 2 equations

y = - 5x + 1 → (1)

y = - x - 3 → (2)

Since both are expressed in terms of y, equate the right sides, that is

- x - 3 = - 5x + 1 ( add 5x to both sides )

4x - 3 = 1 ( add 3 to both sides )

4x = 4 ( divide both sides by 4 )

x = 1

Substitute x = 1 into either of the 2 equations and evaluate for y

Substituting into (2)

y = - 1 - 3 = - 4

Solution is (1, - 4 )

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b

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius

The circle shown is centred at the origin and has a radius of 5, thus

x² + y² = 5² ⇒ x² + y² = 25 → b

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3 years ago
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Which statements are true?
Rina8888 [55]

Answer:

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Step-by-step explanation:

Absolute value is the distance to zero, and it is always positive. That means the positive and negative versions of a number have the same absolute value. That means the first one is true, and the second and third ones are false. For the last one, -6 is closer to zero, so that means it would be true (The absolute value of -6 is 6, and the absolute value of -7 is 7).

4 0
3 years ago
Find two values for k such that the trinomial x2 – 7x + k can be factored over the integers. Explain your reasoning.
vova2212 [387]

Answer:

1) For a = 1: b = 6 and k = 6, 2) For a = 3: b = 4 and k = 12

Step-by-step explanation:

The polynomial y = x^{2} - 7\cdot x + k is a second-order polynomial of the form (x-a)\cdot (x-b) = x^{2}-(a+b)\cdot x + a\cdot b. By direct comparison, we construct the following system of equations:

a + b = 7 (1)

a\cdot b = k (2)

By (1) we know that there are a family of pairs such that the system of equations is satisfied. Let suppose that both a and b are integers. We assume two arbitrary integers for a:

1) a = 1

b = 7 - a

b = 6

a\cdot b = k

k = (6)\cdot (1)

k = 6

2) a = 3

b = 7 - a

b = 4

a\cdot b = k

k = (3)\cdot (4)

k = 12

6 0
3 years ago
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