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suter [353]
3 years ago
13

Answer fast pleaseee, Solve the following system of equations: y= -5x +1 and y= -x-3

Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer:

x=1 y=-4

Step-by-step explanation:

USPshnik [31]3 years ago
5 0

Answer:

(1, - 4 )

Step-by-step explanation:

Given the 2 equations

y = - 5x + 1 → (1)

y = - x - 3 → (2)

Since both are expressed in terms of y, equate the right sides, that is

- x - 3 = - 5x + 1 ( add 5x to both sides )

4x - 3 = 1 ( add 3 to both sides )

4x = 4 ( divide both sides by 4 )

x = 1

Substitute x = 1 into either of the 2 equations and evaluate for y

Substituting into (2)

y = - 1 - 3 = - 4

Solution is (1, - 4 )

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6 0
2 years ago
We were never taught this in class, and I understand it, kind of... but i'm just confused with everything.
GaryK [48]
\bf \cfrac{x^3y}{xy^5}\cdot \cfrac{x^2y^9}{x^8}\implies \cfrac{x^3x^2y^1y^9}{x^1x^8y^5}
\\ \quad \\
\textit{now, using exponent rules, same base, different exponent}
\\ \quad \\
\cfrac{x^{3+2}y^{1+9}}{x^{1+8}y^5}\implies \cfrac{x^5y^{10}}{x^9y^5}\\
----------------------------\\\bf \textit{now, keep in mind that}
\\ \quad \\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
%  negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 

\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}
\\ \quad \\
thus\\
----------------------------\\
\bf \cfrac{x^5y^{10}}{x^9y^5}\implies \cfrac{x^5y^{10}}{1}\cdot \cfrac{1}{x^9}\cdot \cfrac{1}{y^5}\implies x^5y^{10}\cdot x^{\boxed{-9}}\cdot y^{\boxed{-5}}
\\ \quad \\
x^5x^{-9}y^{10}y^{-5}\implies x^{5-9}y^{10-5}\implies x^{-4}y^5
\\ \quad \\
\cfrac{1}{x^{\boxed{4}}}\cdot \cfrac{y^5}{1}\implies \cfrac{y^5}{x^4}
8 0
3 years ago
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