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pshichka [43]
3 years ago
13

Who can help me with these quick problems?

Mathematics
1 answer:
olasank [31]3 years ago
6 0
Don’t press the link it a scam
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Simplify<br> (−2a^2b^4)^3
padilas [110]

Answer:

--\frac{8a^6}{b^12}

Step-by-step explanation:

3 0
3 years ago
What is the cosine of angle F <br><br>A. 4/5<br>B. 3/4<br>C. 5/4<br>D. 3/5​
saveliy_v [14]

Answer: option D

Step-by-step explanation:

Remember the cosine identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

adjacent=15\\hypotenuse=25

Now you can substitute values into  cos\alpha=\frac{adjacent}{hypotenuse} and then reduce the fraction.

THerefore you get:cos(F)=\frac{15}{25}\\\\cos(F)=\frac{3}{5}

6 0
3 years ago
Read 2 more answers
Paul sketched a right angel with legs of length a, b, and h. Then he writes an expression for the length of the hypotensure. Wha
MA_775_DIABLO [31]

Answer:

Paul might have written the expression h^2=a^2+b^2.

Step-by-step explanation:

Given:

Length of the leg 1 = a

Length of the leg 2 = b

Hypotenuse = h

We need the expression Paul has written:

Solution:

Now we know that;

The figure sketched by Paul is a right angle triangle.

Now by Pythagoras Theorem which states that;

"The square of the length of the hypotenuse is equal to sum of the square of the length of the legs."

equation can be framed as;

h^2=a^2+b^2

Hence Paul might have written the expression h^2=a^2+b^2.

4 0
3 years ago
Bomdas can someone help me with this 32-7×4+42÷6×3
monitta

25, 7*4 = 28 32-28=4 and 42/6=7*3 = 21 + 4 = 25

6 0
3 years ago
Read 2 more answers
Graph f(x)=4x calculate the initial value of the function
tekilochka [14]

Answer:

Step-by-step explanation: your going to find the y intercept

find the domain

find the inverse

find the derivative

find the extrema

find the horizontal asymptotes

tell weather its even or odd

but its X=0

4 0
3 years ago
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