Let the middle point be M.
MDC is a isometric triangle.
∠MDC = MCD = 25°
∠DBC = 180-25-25-35 = 95°
How I Was Taught You Do Foil F-First O-Outer I-Inner L-Last So You Would Multiply First Number With The Other First Number Which Is The 4b×4b=16b² Then You Solve The Outer 4b+1 Then The Inner -1+4b & The Last -1+1
~Hope This Helps
You just divide 0.72 by 0.36 which gives you 2. then you multiply that by 2 which gives you an answer of 4
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>