Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer:
False
Step-by-step explanation:
The surface area of the cone is
The surface area of the cylinder is:
hope to help
Step-by-step explanation:
carry on learning
Answer:
$11 and $16
Step-by-step explanation:
let x be the cost of a student ticket then an adult ticket is x + 5 , then
3x + 7(x + 5) = 145 , that is
3x + 7x + 35 = 145
10x + 35 = 145 ( subtract 35 from both sides )
10x = 110 ( divide both sides by 10 )
x = 11
Student ticket costs $11 and adult ticket = x + 5 = 11 + 5 = $16
5 2/4 because 3 and 2 are 5 and 1/4 plus 1/2 make up 2/4 meaning its either 5 2/4 or 5 1/2
now i get brainly <3
