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3 years ago

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Compare the area of a rectangle whose sides are 3 and 1/9 inches by 4 and 2/3 inches to a rectangle whose sides are 3 and 2/3 in

ches by 4 and 1/5 inches. Which is greater? By how much? Answer in inches.

1 answer:

Fittoniya [83]3 years ago

4 0

Rectangle 1. p. 146 in
rectangle 2. p. 146 in

the perimeters are the same. the rectangles are equal

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Select a counter-example that makes the conclusion false.

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Kyle is setting out Japanese food for a party he is having. He has 9 avocado rolls and 18 cucumber rolls. If he wants each plate

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Kyle can make 9 plates, each containing 1 avocado roll and 2 cucumber rolls.

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4 years ago

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A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

<em>Multiplying both sides by 16 we get:</em>

<em /> $256=3x^2$ <em />

<em>Dividing both sides by 3 we get:</em>

<em /> $\frac{256}{3} =x^2$ <em />

<em>Using square root on both sides we get:</em>

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

<em>So, the base of triangle = </em> $\frac{8}{\sqrt{3}} \ m.$ <em />

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

<em>Thus, the height of triangle = </em> $\frac{12}{\sqrt{3}} \ m.$ <em />

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago