The answer is 30.
First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.
This may help:
96/3=32
32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93
So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.
9514 1404 393
Answer:
a) ∆ABC ~ ∆EDC by AA similarity
b) ED/AB = 3/4
c) 15 cm
Step-by-step explanation:
a) Two angles in each triangle are the same, so the AA similarity postulate can be used to declare the ∆ABC ~ ∆EDC. (Each triangle includes a right angle and angle C.)
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b) Corresponding sides are ED/AB, DC/BC, EC/AC. The ratio of corresponding sides is ED/BC = (12 cm)/(16 cm) = 3/4.
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c) Using the ratios identified above, we have ...
DC/BC = 3/4 = x/(20 cm)
x = 3/4(20 cm)
x = 15 cm
Answer:
Step-by-step explanation:
Hello There!
Remember: sum of interior angles of a triangle = 180
so to find x we use this equation
180 = 90 + 7x + 5 + 9x + 5 ( the little square in the triangle indicates that the angle is a right angle. right angles have a measure of 90 so that's where the 90 came from.)
now we solve for x
step 1 combine like terms
90 + 5 + 5 = 100
7x + 9x = 16x
now we have 180 = 16x + 100
step 2 subtract 100 from each side
180 - 100 = 80
100 - 100 cancels out
now we have 80 = 16x
step 3 divide each side by 16
80/16 = 5
16x/16=x
we're left with x = 5
Finally we plug in 5 into x for angle a
7(5)+5
7*5=35
35+5=40
so we can conclude that the measure of angle A is 40 degrees
1) Draw the coordinate plane
2) Draw the line y = - 2
It is a line parallel to the y axis, two units below the origin
3) The solution (graph of the inequality y < - 2) is all the area below the line y = - 2.
