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ad-work [718]
3 years ago
6

Having trouble with this too

Mathematics
1 answer:
elixir [45]3 years ago
5 0
If Angel ran a full lap in two minutes, then she ran half of a lap in one minute. If a lap is 2/5 kilometers, the half a lap is 1/5 kilometers.
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In the triangle below x= ? cm. Round to the nearest tenth
DIA [1.3K]
Hope this helps you out!!!!!

4 0
3 years ago
Is it a, b , c , or d?​
IrinaVladis [17]

The line has a positive slope. Let's look at all the slopes:

1) -3

2) -3

3) 3

4)3

Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.

The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.

1) y = -3/2x - 5/2

2) y = -3/2x + 5/2

We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.

The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.

5 0
3 years ago
2+90=? <br> please someone help asap
Oxana [17]

Answer:

92 :)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
-5/2x-19/10 <br><br> Plss Answer this in fraction form, and simplified, I can't figure it out!
Alja [10]

Answer:

= -25x-19/10

Step-by-step explanation:

8 0
2 years ago
A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random
g100num [7]

Answer:

97.4% probability

Step-by-step explanation:

Since there is only two possible outcome of inspecting the catridge : either defective or not, we can solve the problem using the binomial probability distribution (approximated to normal).

To approximate the binomial probability to normal, we find the expected value and the standard deviation of the probability of exactly x sucesses on n repeated trials with p probability

Expected values E(X) = np

Standard deviation √V(X) = √np(1-p)

using the z-score formula (X - μ)/σ, we can solve normally distributed problem.

Where μ is the mean and σ is the standard deviation. The Z-score is is the measure of how much a sample is from the mean. The p-value associated with this z-score which is the probability that the value of the measure is smaller than X can be checked on the z-score table.

FOR THIS QUESTION,

a random sample of 200 cartridges is selected

n = 200

Therefore If there are more than 0.02 × 200 = 4 defective, the sample will be returned.

To determine the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05

μ = E(X)

= 0.05 × 200 = 10

σ = √V(X) = √np(1-p)

= √200 × 0.05 × 0.95

= 3.08

This probability is 1 subtracted by the pvalue of Z when X =4

Z = (X - μ)/σ

Z= (4 - 10)/3.08

Z = -1.95

Z = -1.95 has a P-value of 0.026 (on the z-score table)

This means that there is a 1 - 0.026 = 0.974

= 97.4% probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05.

6 0
3 years ago
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