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deff fn [24]
2 years ago
13

44 ounces = ? Pounds Please answer I really do not understand

Mathematics
2 answers:
tatuchka [14]2 years ago
7 0
44 ounces=2.75 pounds
Alexeev081 [22]2 years ago
5 0
44 ounces equals 2.75 pounds. Because 1 pound equals 16 ounces. So if you divide 44 by 16, then you will get 2.75.
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Marco and his two younger sisters would like to purchase a silver charm bracelet for their mother’s birthday. they went to the m
ioda

Function would be f(x) = 5x+85

here, x= 15

5(15)+85 = 75+85 = $160

8 0
2 years ago
51 more than y is greater than -240
svet-max [94.6K]

Answer:

y + 51 ≥ -240

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
To win a basketball game, one team scored 113 points. They made a total of 41 two pointers and three pointers how many of the ba
anyanavicka [17]
So there are 41 two pointers and three pointers.  
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6 0
3 years ago
A random sample of 850 births included 434 boys. Use a 0.10 significance level to test the claim that 51.5​% of newborn babies a
Molodets [167]

Answer:

A

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

z = -0.257

P value = P(Z<-0.257) = 0.797

Decision; we fail to reject the null hypothesis. That is, the results support the belief that 51.5​% of newborn babies are​ boys

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

Given;

n=850 represent the random sample taken

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 850

po = Null hypothesized value = 0.515

p^ = Observed proportion = 434/850 = 0.5106

Substituting the values we have

z = (0.5106-0.515)/√(0.515(1-0.515)/850)

z = −0.256677

z = −0.257

To determine the p value (test statistic) at 0.10 significance level, using a two tailed hypothesis.

P value = P(Z<-0.257) = 0.797

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = -0.257) which falls with the region bounded by Z at 0.10 significance level. And also the one-tailed hypothesis P-value is 0.797 which is greater than 0.10. Then we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that at 10% significance level the null hypothesis is valid.

5 0
3 years ago
8z=4(2z+1) show step by step
Verizon [17]
8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.
5 0
3 years ago
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