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3 years ago

Which answer choice represents an equivalent number sentence of "15 + (3 - 8)"?

Mathematics

2 answers:

frozen [14]3 years ago

8 0

Answer:

A- 15-5 is the same

Step-by-step explanation:

15 + (3-8)

15 + (-5)

15-5

Maksim231197 [3]3 years ago

5 0

I believe the answer is C

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The number of males in the classroom is three more than twice the number of females. Of the total number of students is 57, how

dolphi86 [110]

Answer:

Step-by-step explanation:

Given that the number of males in the classroom is three more than twice the number of females.

the total number of students is 57

Let x be the no of males then no of females = $57-x$

Also we have 3 more than twice no of females as

$2(57-x)+3$

This equals x

$2(57-x)+3=x\\114-2x+3=x\\3x=117\\x=39$

No of males = 39, no of females = 18

6 0

3 years ago

Bro helpppppfrpeagera

Oksana_A [137]

Answer:

bro whatisthequestion

4 0

2 years ago

Read 2 more answers

What is the solution for −40 = 10c? A. c = 1 B. C = -1 C. c = -4 D. c = 4

Aleks [24]

Answer:

C. c = -4

Step-by-step explanation:

you must get c by itself. you have to divide both sides by 10. this gets rid of the 10c and keeps both sides equal

-40/10 = c

c = -4

5 0

3 years ago

Find the slope of the line that passed though the two points (0,5) and (-9, -4)

OverLord2011 [107]

To find the slope, use the slope(m) formula:

$m=\frac{y_2-y_1}{x_2-x_1}$ and plug in the two points

(0, 5) = (x₁, y₁)

(-9, -4) = (x₂, y₂)

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-4-5}{-9-0}$

$m=\frac{-9}{-9}$ [two negatives cancel each other out and become positive]

m = 1 The slope is 1

6 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago