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Hoochie [10]
3 years ago
6

If you do all o these I will give you 5000 points every month

Mathematics
2 answers:
saw5 [17]3 years ago
6 0
1. find the LCD of 3 and 4 (12). so now your fractions are 5 4/12 and 3 9/12 perimeter is 2l + 2w so 2 (5 4/12) + 2( 3 9/12) = 10 4/12 + 7 6/12 = 17 10/12 or 17 5/6. this is reasonable because that the average perimeter of a sandbox.
2. LCD again is 12, so the fractions are 5 10/12 and 2 1/12. turn those into mixed fractions and get 70/12 and 25/12. 45/12 or 3 3/4. So she babysits 3 3/4 hours during the week.
3. The LCD for this is 8. now the fractions are 2/8 and 1 7/8 or 15/8. add 15/8 and 2/8 to get 17/8 or 2 1/8. He is using a total of 2 1/8 cups of flour.
4. 0.2
5. 0.054
6. 0.024

dont give me those points XD
stealth61 [152]3 years ago
5 0
1. find the LCD of 3 and 4 (12). so now your fractions are 5 4/12 and 3 9/12 perimeter is 2l + 2w so 2 (5 4/12) + 2( 3 9/12) = 10 4/12 + 7 6/12 = 17 10/12 or 17 5/6. this is reasonable because that the average perimeter of a sandbox.
2. LCD again is 12, so the fractions are 5 10/12 and 2 1/12. turn those into mixed fractions and get 70/12 and 25/12. 45/12 or 3 3/4. So she babysits 3 3/4 hours during the week.
3. The LCD for this is 8. now the fractions are 2/8 and 1 7/8 or 15/8. add 15/8 and 2/8 to get 17/8 or 2 1/8. He is using a total of 2 1/8 cups of flour.
4. 0.2
5. 0.054
6. 0.024
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Anec 2 Matemáticas
Rama09 [41]

Answer:

a) 1 : 100

1 cm en el mapa equivalen a 100 cm en la realidad

b) 1 : 1000

1 cm en el mapa equivalen a 1000 cm en la realidad

c) 1 : 2000

1 cm en el mapa equivalen a 2000 cm en la realidad

d) 1 : 18000

1 cm en el mapa equivalen a 18000 cm en la realidad

Step-by-step explanation:

Tenemos 4 escalas :

a) 1 : 100

b) 1 : 1000

c) 1 : 2000

d) 1 : 18000

Definimos ''escala'' como una relación entre dos números ''a'' y ''b'', generalmente ''a'' y ''b'' son números naturales. Denotamos la escala como :

a : b

En dónde ''a'' representa la longitud del dibujo y ''b'' la longitud real.

Por ende, cuando a estamos en presencia de una escala de reducción y cuando a>b estamos en presencia de una escala de ampliación.

La escala a=b ó 1 : 1 se define como escala natural.

Analicemos cada caso :

a) 1 : 100

Aquí vemos que es una escala de reducción (dado que 1 < 100) por ende cualquier magnitud de longitud en el mapa será 100 veces más grande en la vida real.

En este caso, 1 cm en el mapa equivalen a 100 cm en la realidad.

Análogamente y con el mismo razonamiento, escribimos las relaciones para los casos b), c) y d)  

b) 1 cm en el mapa equivalen a 1000 cm en la vida real

c) 1 cm en el mapa equivalen a 2000 cm en la vida real

d) 1 cm en el mapa equivalen a 18000 cm en la vida real

b), c) y d) también representan escalas de reducción.

7 0
3 years ago
Please help me with this problem, and can you also show steps. thank you
Maurinko [17]
Convert all the improper fractions into mixed numbers, then simplify. Then, you do the operations.
7 0
3 years ago
Read 2 more answers
How does place value help me divide
Anna71 [15]
Place value helps you divide because it helps you to know where to put the numbers
3 0
3 years ago
Read 2 more answers
Somebody, please help
SashulF [63]
F(x) can be written as:
f(x) = Asin(2x); where A is the amplitude and the period of the function is half that of a normal sin function.
f(π/4) = 4
4 = Asin(2(π/4))
4 = Asin(π/2)
A = 4
Amplitude of g(x) = 1/2 * amplitude of f(x)
A for g(x) = 2
g(x) = 2sin(x)
5 0
3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
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