Question

A cone-shaped tent has a diameter of 12 ft and a height of 6 ft.

Answer 1

Here's the formula for the volume of a cone:

$V=\frac{1}{3}\pi\ r^2h$

Plug in 3.14 for $\pi$.
Plug in 6 for the height $h$.
Our radius is half of our diameter. $r=6$.

$V\approx\frac13\times3.14\times6^2\times6$

6² = 6 × 6 = 36.
Now we just multiply together 1/3, 3.14, 36, and 6 to get...

$V\approx226.08$

Rounding to the nearest tenth...

$\boxed{V\approx226.1\ ft^3}$

Answer 2

Cone formula: 1/3($\pi r^{2} h)$
     
Step 1(Fill in formula): 1/3((3.14)($6^{2}$)(6))
Step 2 (Solve): 1/3((3.14)(36)(6))
Step 3 (Solve): 1/3(678.24)
Step 4 (Complete) : 226.08ft³