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marishachu [46]
3 years ago
12

Dilbert forgot to study for the multiple-choice exam. Each question has four choices and there are 50 questions. Dilbert, in his

infinite wisdom, decides to randomly guess on each problem. Find the probability for each: a) If Dilbert gets 30 or more right, he will be named the company CEO. b) If Dilbert gets 20 to 29 right, he will be promoted and get a 10% raise. c) If Dilbert gets 10 to 19 right, he will get to keep his menial job and pay. d) If Dilbert gets less than 10 right, he will be kicked out of cubicle central and unemployed.
Mathematics
1 answer:
Aloiza [94]3 years ago
4 0
1. 30 ÷ 50 = 0.6 = 6%
2. 20 ÷ 50 = 0.4 = 4%
29 ÷ 50 = 0.58 = 58%
3. 10 ÷ 50 = 0.2 = 2%
19 ÷ 50 = 0.38 = 38%
4. 5 ÷ 50 = 0.1 = 1%



I can't say for sure if these are the corrects answers, as math is not one of my better suits. But, I hope that it can somewhat help you.
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Which function has an inverse function?
daser333 [38]

Answer: Option B

Step-by-step explanation:

By definition, only those functions that are one to one have an inverse function.

A function is one by one if there are not two different input values, x_1 and x_2, that have the same output value y

Note that the function f(x)= \frac{|x+3|}{5}  is not a one-to-one function

When x=2  f(x)= \frac{|2+3|}{5}=1\ ,\ \ y=1

When x=8  f(x)= \frac{|-8+3|}{5}=1\ \ ,\ y=1

Note that the function f(x)= \frac{x^4}{7}+ 27  is not a one-to-one function

When x=1 f(x)= \frac{(1)^4}{7}+27\ ,\ \ y=\frac{190}{7}

When x=-1  f(x)= \frac{(-1)^4}{7}+27\ ,\ \ y=\frac{190}{7}

Note that the function f(x)= \frac{1}{x^2}  is not a one-to-one function

When x=1 f(x)= \frac{1}{(1)^2}\ ,\ \ y=1

When x=-1  f(x)= \frac{1}{(-1)^2}\ ,\ \ y=1

Then the answer is the option B.

You can verify that The function f (x) = x ^ 5-3 is a one-to-one function and therefore its inverse is a function

5 0
3 years ago
In triangle RST, m∠R > m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
solmaris [256]

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
  2. disprove the statement by finding a counterexample

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

  1. The left side of this inequality is 2*m∠R
  2. The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

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Step-by-step explanation:

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Answer:

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