<h3><u>Answer</u> :</h3>
See the attachment for better understanding.
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u>: Length of string (AC) = 300ft
<u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u> </u>: Height of the kite from ground (AB)





Hope it helps !
Answer:
Step-by-step explanation:
The only way I know is to divide the centimeters by 30.48
Answer:
B.
R (2,4)
soln
center(h,k)=(6,1)
radius (r)=5units
so
eqn of circle is (x-6)^2+(y-1)^2=5^2
2 2
or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle
Answer:
(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)
Answer:
(1/4)*(e⁶ - 7)
Step-by-step explanation:
a) Given
x − y = 0 if x = 0 ⇒ y = 0
x − y = 2 if x = 0 ⇒ y = -2; if y = 0 ⇒ x = 2
x + y = 0 if x = 0 ⇒ y = 0
x + y = 3 if x = 0 ⇒ y = 3; if y = 0 ⇒ x = 3
then we show the region R in the pics 1 and 2.
b) We make the change of variables as follows
u = x + y
v= x - y
If
x - y = 0 ⇒ v = 0
x − y = 2 ⇒ v = 2
x + y = 0 ⇒ u = 0
x + y = 3 ⇒ u = 3
Where u is the horizontal axis and v is the vertical axis, the new region S is shown in the pic 3.
c) We evaluate ∫∫R (x + y)*e∧(x² - y²)dA
The procedure is shown in the pic 4, where we have to calculate the Jacobian in order to use it to get the answer.