For the given question the answer to the first part is that frequency of sound will be 404.76 Hz. and answer to the second part will be that the initial frequency for which that place will have the highest level of sound intensity
Given, the speed of sound 340 m/s
a) L1 + L2 = 3.5 m
and Ld = | L1 - L2 | = ( 1.75 + 0.21 ) - (1.75 - 0.21 ) = 1.96 - 1.54 = 0.42 m
Ld = λ/2
λ = 2Ld = 2×0.42 = 0.84 m
and finally,
f = v/λ
f = 340/0.84
f = 404.76 hertz
Frequency came out to be 404.76 hertz in this case
b) For the first frequency
0.42 = λ
f = v/λ
f = 340 / 0.42
f = 809.52 Hertz
Frequency came out to be 809.52 Hertz in this case.
To conclude with we can say that the Frequency of the sound in case on came out to be 404.76 hertz which is approximately 405 Hz after applying all the concepts and calculations, in second case first frequency for which that location will be a maximum of sound intensity came out to be 809.52 Hertz after applying all the concepts and calculations.
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Become more positive instead of negative
Answer:
Vf = 78.64 m/s
Explanation:
The rocket is travelling upward at a constant acceleration of 3.99 m/s² until it runs out of fuel. So, in order to calculate its velocity at the point, where it runs out of fuel, we can simply use 3rd equation of motion:
2as = Vf² - Vi²
where,
a = acceleration = 3.99 m/s²
s = distance or height covered by rocket till fuel runs out = 775 m
Vf = Final Velocity = ?
Vi = Initial velocity = 0 m/s (Since, rocket starts from rest)
Therefore,
2(3.99 m/s²)(775 m) = Vf² - (0 m/s)²
Vf = √(6184.5 m²/s²)
<u>Vf = 78.64 m/s</u>
static friction is acting on stationery object (rest) but kinetic friction acting on a moving body.
The other one is static friction oppose the object to start a motion so it force is great than kinetic friction
Answer:
The objects have the same altitude at the same time in the heights 22.4m and 36.6m.
Explanation:
The equation of the position of the hot air balloon with respect to time is:
And the equation of the position of the pellet with respect to time is:
As the altitude of the two objects must be equal, we can match these equations, so:
Solving this equation for t, we obtain:
Now, using the equation of the position of the balloon (we can use the other either, but the first one is easier) we can obtain the height of the places where the two objects have the same altitude at the same time:
In words, the hot air balloon and the pellet have the same altitude at the same time in the heights 22.4m and 36.6m.