The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m
Explanation:
Let's solve this problem in parts
let's start by finding the intensity of the sound in each observer
observer A β = 59 db
β = 
where I₀ = 
W / m²
= 
W / m²
Similarly for Observer b 
now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed
P = I A
therefore for the two observers
the area of a sphere is
we substitute the above formula, we get
Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute
after solving the above equation we get x = 28.64 m
This is the distance of observer A
similarly The distance from observer B is 35 - x
= 40 - 28.64
= 11.36m
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..... equal to the force from the engine pushing the car forward.
That's why the car is not accelerating. The horizontal forces on it
are balanced.
Answer: 70 N to the East
Explanation:
lets assume east is positive and west is negative, since they are in opposite directions the net external force = F1+F2
Net force = (-60) + 130
Net force = 70
or
Net force = 70 N in the east direction
Answer: A reference point
Explanation: If an object is in motion then its distance from another object is changing. Whether an object is moving or not depends on your point of view. For example, a woman riding on a bus is not moving in relation to the seat she is sitting on, but she is moving in relation to the buildings the bus passes. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.
Radiocarbon saying assume the half life for radioistopes change over time. The half life of C -14 is 5730 years
