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suter [353]
3 years ago
15

Does this equation y=87.2/x represent a direct or inverse variation?

Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

Inverse relationship

Step-by-step explanation:

The equation we are looking at is;

y = 87.2/x

which implies xy = 87.2

If it was a direct relationship

y = constant * x

if it was inverse, it would have been

y * x = constant

since 87.2 is a constant, the question looks exactly like the second scenario.

This means that what we have is an inverse relationship

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Aubrey worked at the concession stand during a recent sporting event at her high school. During the first hour of the event, she
ella [17]

Answer:

cost of nachos = $3.45

Cost of tacos = $1.5

Step-by-step explanation:

Let

x = cost of nachos

y = cost of tacos

11x + 18y = 64.95 (1)

6x + 15y = 43.20 (2)

Multiply (1) by 6 and (2) by 11 to eliminate x

66x + 108y = 389.70

66x + 165y = 475.20

Subtract to eliminate x

165y - 108y = 475.20 - 389.70

57y = 85.50

y = 85.50/57

y = 1.5

Substitute y = 1.5 to find x

11x + 18y = 64.95 (1)

11x + 18(1.5) = 64.95

11x + 27 = 64.95

11x = 64.95 - 27

11x = 37.95

x = 37.95/11

x = 3.45

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8 0
3 years ago
Center: (10,-10)
vova2212 [387]

This is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

What is the ellipse?

The equation for an ellipse is typically written as x² a²  + y² b² = 1. x²  a² + y² b²  = 1. An ellipse with its origin at the center is defined by this equation. The ellipse is stretched further in both the horizontal and vertical directions if a > b, a > b, and if b > a, b > a, respectively.

The standard form of the equation of an ellipse with center (h, k)and major axis parallel to the x-axis is:

\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1

where,

a > b

the length of the major axis is 2a

the coordinates of the vertices are (h±a,k)

the length of the minor axis is 2b

the coordinates of the co-vertices are (h,k±b)

the coordinates of the foci are (h±c,k),

where c² = a² − b².

so,

\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

Hence, this is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1.

To learn more about ellipse, visit

brainly.com/question/16904744

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7 0
11 months ago
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