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Dima020 [189]
2 years ago
10

Hello, is there anyone here a pharmacy technician?

Mathematics
1 answer:
m_a_m_a [10]2 years ago
5 0
Answer:

Maybe

Explanation:

…
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Solve for r.
Reika [66]

Answer:

r=-45

Step-by-step explanation:

<u>r/5=-9</u>

OUR GOAL: To isolate the variable "r" on one side...

1) Multiply both sides of the equation by 5 to get r on one side:

r=-9*5

2) Multiply:

r=-45

Let me know if you have any question

4 0
3 years ago
Read 2 more answers
What is community property and associative property
hichkok12 [17]
It's "commutative property," which says that (for addition/multiplication) order of the operator doesn't matter. For eg, 3 * 5 = 5 * 3. 

Associative property (again, of multiplication and addition) means that it doesn't matter how you solve an expression if the same operand is used and some numbers are grouped. For eg. 3 * (5 * 4) = (3 * 5) * 4.
4 0
3 years ago
Factor completely: <br> x^3 - x^2 - 6x
PSYCHO15rus [73]

Answer:

x(x-3)(x+2)

Step-by-step explanation:

1. Find the GCF (Greatest Common Factor)

GCF=x

2. Factor out the GCF and simplify.

x(x^{2} -x-6)

3. Factor x^{2} -x-6.

Which two numbers add up to -1 and multiply to -6?

<u>-3 and 2</u>

Rewrite the expression using the numbers above.

(x-3)(x+2)

4. Done!

x(x-3)(x+2)

4 0
3 years ago
The shapes nelow are shaded to show two different fraftions, Are the fractions equivalent? Use the drop down menus to best expla
katovenus [111]

Answer:

Yes they are equivalent.

Step-by-step explanation:

They each represent one half.

5 0
3 years ago
Question 2 please fas
Len [333]

Answer:

a = 3, b = 2

Step-by-step explanation:

It is given that both the polynomials are equal.

Therefore, h(x) = k(x)

{x}^{3}  + (a + b) {x}^{2}  - 4x + 2 \\  =  {x}^{3}  + 5 {x}^{2}  - (2a - b)x + 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\ (a + b) {x}^{2}  = 5 {x}^{2}   \\  \implies \: a + b = 5.....(1) \\  \\  - (2a - b)x =  - 4x \\ 2a - b = 4....(2) \\  \\ adding \: equations \: (1) \: and \: (2) \\  \\ 3a = 9 \\   \implies \: a =  \frac{9}{3}  \\   \huge \red{ \boxed{\implies \: a = 3}} \\  \\ substituting \: a = 3 \: in \: equation \: (1) \\ 3 + b = 5 \\   \implies \: b = 5 - 3 \\ \huge \purple{ \boxed{ \implies  b = 2}}

5 0
3 years ago
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