Answer:
f(x + 1) = -(3/4)*f(x)
(second option)
Step-by-step explanation:
Here we have the sequence:
64, -48, 36, -27, ...
First, we can notice two things:
Each term has a different sign than the previous term, so the relation is something like:
f(x + 1) = -k*f(x)
Now to find the value of k, we can just replace some of the values (for example, the first and the second one)
-48 = -k*64
48/64 = k
3/4 = k
Now, if we use any pair of consecutive terms we should get the same value of k, now let's try to use the second and third terms to see if we get the same value of k:
36 = -k*(-48)
36 = k*48
36/48 = k
3/4 = k
We got the same value, so we can conclude that k = (3/4)
Then the relation that describes this sequence is:
f(x + 1) = -(3/4)*f(x)
Answer:
00
Step-by-step explanation:
I hope this helps you
-2p <20-4
-2p <16
-p <8
p> -8
Answer:
Part a) The radii are segments AC and AD and the tangents are the segments CE and DE
Part b) 
Step-by-step explanation:
Part a)
we know that
A <u>radius</u> is a line from any point on the circumference to the center of the circle
A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.
In this problem
The radii are the segments AC and AD
The tangents are the segments CE and DE
Part b)
we know that
radius AC is perpendicular to the tangent CE
radius AD is perpendicular to the tangent DE
CE=DE
Triangle ACE is congruent with triangle ADE
Applying the Pythagoras Theorem

substitute the values and solve for CE





remember that
CE=DE
so

Answer:
The current is 0.08 ampere.
Step-by-step explanation:
Given:
The current is 1/2 ampere when the resistance is 400 ohms.
Now, the current I in an electrical conductor varies inversely as the resistance R of the conductor.
So, as per formula 
Solving for "k" using the current 1/2 amperes when the resistance is 400 ohms.

By cross multiplication we get:

Putting the value of
for solving the equation:

Now, the current when the resistance is 2500 ohms:


ampere.
Therefore, the current is 0.08 ampere.