I'm not sure if this is right, but I multiplied 115 by 4 and got 460- Try that? ;^;
Answer:
B. 5x^4+5x^3
Step-by-step explanation:
(f.g)(x) = f(x) * g(x) = 5x^3 * (x+1)
= 5x^3 * x + 5x^3 * 1
= 5x^4 + 5x^3
Outcomes in a sample space :)
Hmm I’m not so sure but can you help me with this? If 150 Joules of work is needed to move a box 1000 cm, calculate the force that was used?
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
