Ask question

Ask question

All categories

3 years ago

8

Triangle JKL has measures as follows: KJL=(6x-1), JLK=75, LKJ=(11x+4) What is the measures of angle KJL?____________ DOESN'T PRO

VIDE PICTURE!

2 answers:

ivann1987 [24]3 years ago

7 0

Answer:

Its B and D

Step-by-step explanation:

madreJ [45]3 years ago

4 0

It is b and d because 11x+4 will equal that

You might be interested in

How do I do this question folks?

horsena [70]

Answer:

Correct answer: B

Step-by-step explanation:

Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.

In the graph, you can see that the graph is defined for $-3\leq x < 1$ (not-including 1 because there is an open hole there, indicating it is not part of the domain), and $2\leq x\leq 4$ .

Now that we know the domain, we can attach it to the graphs that lie on those domains.

We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.

At this point, you can just start crossing off answers that don't meet this criteria.

Cheers!!

7 0

3 years ago

Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}

stepan [7]

We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.

We need to remove in order to make the relation a function.

<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>

In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.

<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>

7 0

3 years ago

Read 2 more answers

Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the

Alborosie

Answer:

Step-by-step explanation:

Let the subscripts d and n represent day and night respectively

The null hypothesis is

H0 : μd ≥ μn

The alternative hypothesis is

H1 : μd < μn

it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.

The decision rule is to reject H0: μd ≥ μn If 0.10 > p value

Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (xd - xn)/√σd²/nd + σn²/nn

Where

xd and xn represents sample means for day and night respectively.

σd and σn represents population standard deviations for day and night respectively.

nd and nn represents number of samples

From the information given,

xd = 334

xn = 341

σd = 23

σ2 = 28

nd = 60

nn = 68

z = (334 - 341)/√23²/60 + 28²/68

= - 7/√20.34607843138

z = - 1.55

From the normal distribution table, the probability value corresponding to the z score is 0.061

Since the level of significance, 0.1 > 0.061, we would reject H0

Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.

8 0

3 years ago

What is the solution to the compound inequality in interval notation?

Eduardwww [97]

First solve the 2 inequalities for x:-

x > 0 or x <= -5

The last choice is the correct one.

5 0

4 years ago

Read 2 more answers

Algebra 1 polynomials hellllp

defon

A. 40x^2 + 240x + 200
Shape: Rectangle
Formula: A = LW
A = (10x + 10)(4x + 20)
= (10x)(4x) + (10x)(20) + (10)(4x) + (10)(20)
= 40x^2 + 200x + 40x + 200
= 40x^2 + 240x + 200
————————————————————-
2. 57,600 ft^2
Width:
4x + 20 = 160
4x = 140
x = 35
Plug-In:
10x + 10
10(35) + 10
350 + 10
360 = Length
————————————-
A = LW
A = 360 • 160
A = 57,600 ft^2

8 0

2 years ago