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3 years ago

If RS = 12 – 2x, ST = 6x – 5, and RT = 19, find RS. (3 points)

Mathematics

1 answer:

MrRa [10]3 years ago

8 0

Answer:

RS=19

Step-by-step explanation:

Simplify both sides of the equation.

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3 years ago

Read 2 more answers

Intigretion of 1/ sqrt x + qube x

kirill115 [55]

$\displaystyle\int\frac{\mathrm dx}{x^{1/2}+x^{1/3}}$

Let $u=x^{1/6}$ , so that $u^6=x$ and $6u^5\,\mathrm du=\mathrm dx$ . Then $x^{1/2}=x^{3/6}=u^3$ and $x^{1/3}=x^{2/6}=u^2$ .

$\displaystyle\int\frac{6u^5}{u^3+u^2}\,\mathrm du=6\int\frac{u^3}{u+1}\,\mathrm du$

Then with $t=u+1$ , so that $u=t-1$ and $\mathrm du=\mathrm dt$ , we have

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8 0

3 years ago

X:32=250:x<br> Find value of x

Effectus [21]

Answer: sqrt. 8000, 40 sqrt. 5

Step-by-step explanation:

You can set it up as a proportion :

X 250

— = ———-

32 X

Cross multiply :

X^2 = 8000

Solve by square rooting both sides

X=sqrt. 8000 or 40 sqrt. 5

Check

3 0

4 years ago