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2 years ago

The length of a swimming poollane

Mathematics

1 answer:

Hunter-Best [27]2 years ago

8 0

Answer:

x²+5x - 150 = 0

Step-by-step explanation:

Let the length be y and width be x

If the length of a swimming pool is 10 more than 2 times the width, then;

y = 2x+10 ...1

Since the Area is 300m²

A = xy

300 = xy .... 2

Substitute 1 into 2

300 = x(2x+10)

300 = 2x²+10x

Rearrange

2x²+10x - 300 = 0

Divide through by 2

x²+5x - 150 = 0

This gives the required quadratic expression

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What is the domain of f(x)=5x^2 2x-1

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Domain of 5x^2 + 2x - 1 is all real numbers.

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Can you help me solve 13 please 100 points

hoa [83]

Answer: A. 70

Step-by-step explanation:

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3 years ago

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Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2

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Answer:

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = $\sqrt{3}$ , then letting the altitude be h

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1 year ago

The triangles shown below may not be congruent.<br> A. True<br> B. False

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Answer:

B. False

Step-by-step explanation:

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2 years ago

Read 2 more answers

A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The

bulgar [2K]

Answer:

Part a)

Steve's expression is $2(2x+5)^{2}-7$

For x=3, the expression is equal to $235$

Part b)

Jasmine's expression is

$(3x^{2})+(25x)$

For x=2, the expression is equal to $62$

Step-by-step explanation:

Part a)

Let

n-----> the first term

The expression is

$(n-7)$

$n=2(2x+5)^{2}$

substitute

Steve's expression is

$2(2x+5)^{2}-7$

Evaluate for x=3

$2(2(3)+5)^{2}-7=242-7=235$

Part b)

Let

n-----> the first term

Jasmine's expression is

$(3x^{2})+(25x)$

Evaluate for x=2

$(3(2)^{2})+(25(2))=12+50=62$

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