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Darina [25.2K]
3 years ago
8

The length of a swimming poollane

Mathematics
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

x²+5x - 150 = 0

Step-by-step explanation:

Let the length be y and width be x

If the  length of a swimming pool is 10 more than 2 times the width, then;

y = 2x+10 ...1

Since the Area is 300m²

A = xy

300 = xy .... 2

Substitute 1 into 2

300 = x(2x+10)

300 = 2x²+10x

Rearrange

2x²+10x - 300 = 0

Divide through by 2

x²+5x - 150 = 0

This gives the required quadratic expression

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Using the following diagram below, please answer the following:
Colt1911 [192]
The radius of the circle is 15 cm,
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The area of the circle is 706.86 cm^2

The radius is given in the diagram as half the circle, which is 15 cm.

The diameter is double the radius because the diameter measures the circle from edge to edge, so 15•2=30 cm.

The circumference of the circle is 2•3.14•r=C,
2•3.14=6.28, 6.28•15= 94.248 cm.

The area of the circle is 3.14•r^2, so the radius squared is 225 (15•15) and 225•3.14=706.86 cm squared :)
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3 years ago
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Option A

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3 0
3 years ago
Apply the square root principle to solve (x-5)^2-40=0
Nitella [24]

Answer: {5 ± 2√10, 5 - 2√10}

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Next, square root both sides to get x - 5 = ± √40.

Notice that root of 40 can be broken down to 2√10.

So we have x - 5 = ± 2√10.

To get <em>x</em> by itself, add 5 to both sides to get x = 5 ± 2√10.

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As a matter of form, the number will always come before the

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