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Zigmanuir [339]
3 years ago
15

How many 1 inch cubes do you need to create a cube with an edge length of 6 inches?

Mathematics
1 answer:
galben [10]3 years ago
6 0
216 cubes. For the base, you would need 6 x 6 cubes which is 36. Since it is a cube, the height is also 6 so you multiply 36 by 6, which is 216.
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If sarah works 40 hours a week and earns 660 dollars per payroll. how much does she make an hour
Anika [276]

Answer:16.50

Step-by-step explanation: hope it helps

5 0
2 years ago
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Any and all help would be appreciated!
SpyIntel [72]

The way we can find out the unit rate (also known as the <em><u>SLOPE</u></em>) is by using the table as coordinates!

The slope formula is \frac{y2 - y1}{x2 -x1}

With the table, the TIME column can be "x"

The DISTANCE column can be "y"

____________________________

As coordinates, it would look like...

(0,0)

(20, 25)

(30, 37.5) and so on!

_____________________________

All we need to do now is use 2 of these coordinates and plug them into the slope formula in their correct places to find the unit rate!

Example:

solve!

\frac{37.5 - 25}{30 - 20} = 12.5/10 ⇒ 1.25 ( or 5/4 in fraction form)

8 0
3 years ago
A central angle in this diagram is:
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3 0
3 years ago
Write 13/40 as a decimal?
borishaifa [10]
0.325 is the answer. :)

6 0
3 years ago
Read 2 more answers
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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