First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
27/50 is a proper fraction because the numerator is less than the denominator.
Answer:
38 people have a membership.
Step-by-step explanation:
That's because the bottom row shows how many years they've had the membership.
And the y axis shows how many people or the frequency of people having the membership for that amount of years.
So its a bar graph that shows you how many of the members have had the membership for a set amount of years.
So all you have to do is add up each column,
0-2 years = 6 people
2-4 years = 8 people
4-6 years = 10 people
6-8 years = 8 people
8-10 years = 6 people
6 + 8 + 10 + 8 + 6 = 38
Answer:
b. 224
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
In this problem:
We want to find n, when
So






The nearest integer number to 223.9 is 224.
So the correct answer is:
b. 224