X^2 + 5 = 5 + x^2 will give you the same answer. Also know as the commutative property. Answer is (3)
top middle, square, and right triangle. to find perimeter you simply add all of the side lengths :)
Answer: the second one
Step-by-step explanation:
Answer:
m<1 = 39
m<2 = 51
Step-by-step explanation:
For this problem, you need to understand that a little square in the bottom of two connecting lines represents a right-angle (an angle this 90 degrees). This problem, gives you two relationships for angle 1 and angle 2 within a right-angle. Using this information, we can solve for the measures of the two angles.
Let's write the two relations:
m< 1 = 3x
m< 2 = x + 38
And now let's right an equation that represents the two angles to the picture:
m<1 + m<2 = 90
Using this information, let's substitute the expressions we have for the two angles and solve for x. Once we have the value of x, we can find the measure of the two angles.
m< 1 + m< 2 = 90
(3x) + (x + 38) = 90
3x + x + 38 = 90
x ( 3 + 1 ) + 38 = 90
x ( 4 ) + 38 = 90
4x + 38 = 90
4x + 38 - 38 = 90 - 38
4x = 90 - 38
4x = 52
4x * (1/4) = 52 * (1/4)
x = 52 * (1/4)
x = 13
Now that we have the value of x, we simply plug it back into our expressions for the m<1 and m<2.
m<1 = 3x = 3(13) = 39
m<2 = x + 38 = 13 + 38 = 51
And we can verify this is correct with the relational equation:
m<1 + m<2 = 90
39 + 51 ?= 90
90 == 90
Hence, we have found the values of m<1 and m<2.
Cheers.
Answer:
<u>There are 24 orange balls and 130 green balls in the box.</u>
Step-by-step explanation:
Let orange balls be x and green balls be y.
y = 10+5x
x+y = 154
y = 154-x
Now,
y=10+5x
or, 154-x = 10+5x
or, 154-10 = 5x+x
or, 144 = 6x
so, x = 24
Now,
y = 154-x
or, y = 154-24
so, y = 130