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stepladder [879]
3 years ago
13

The double number line shows that 3 back-to-school packages contain 36 pencils.

Mathematics
1 answer:
lord [1]3 years ago
7 0

Answer:

The answer is A

Step-by-step explanation:

i just got it right

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Two trains travel a 160 km track each day. The express travels 10 km h^-1 faster and take 30 minutes less time than the normal t
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Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t

Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.

4 0
3 years ago
WHAT ARE THE COORDINATES OF POINT Q? (-4,2 1/2)
leonid [27]

Answer:

you wrote the answer

Step-by-step explanation:

4 0
2 years ago
Esmerelda bought a bag of jelly beans. There were 24 green jelly beans, which made up 8%, percent of all the jelly beans in the
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So, let's look at the problem once again.

8%, or 8/100 of the bag were green jelly beans.

Let's see what we can do to find out a number of other jelly beans, not including the green ones.

We know that 92% of jelly-beans are not green.

92% is 11.5 times more than 8%
(92/8)

24 (or 8%) times 11.5 = 276

276 - number of jelly beans that are not green.

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Answer: 300 jelly beans were in one bag.
6 0
3 years ago
The radius of the circle whose equation is (x-3)^2 + (y+1)^2 = 16 is
Firdavs [7]

Answer:

4

Step-by-step explanation:

The general equation of a circle with center (a, b) and radius r is given by the equation;

(x-a)^{2}+(y-b)^{2}=r^{2}

The constant in the right hand side of the equation is simply the square of the radius;

We have been given the following equation;

(x-3)^2 + (y+1)^2 = 16

Comparing this with the general equation above;

r^{2}=16\\\\r=\sqrt{16}=4

4 0
3 years ago
This circle is centered at the origin, and the length of its radius iS 6. What is
VikaD [51]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

The equation of circle in standard form can be represented as :

\qquad \sf  \dashrightarrow \:(x - h) {}^{2}  + (y - k) {}^{2}  = r {}^{2}

where,

  • h = x - coordinate of centre = 0

  • k = y - coordinate of centre = 0

  • r = radius of circle = 6 units

now, let's plug in the values :

\qquad \sf  \dashrightarrow \:(x - 0) {}^{2}  + (y - 0) {}^{2}  = 6 {}^{2}

\qquad \sf  \dashrightarrow \: {x}^{2}  +  {y}^{2}  = 36

That's the required equation of circle.

4 0
1 year ago
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