If < A and < B are vertical angles, and < A = 5x - 1 degrees, and < B = 4x + 4 degrees, find x.

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

vertical angles are congruent , so

∠ A = ∠ B , that is

5x - 1 = 4x + 4 ( subtract 4x from both sides )

x - 1 = 4 ( add 1 to both sides )

x = 5

You might be interested in

5 times what is 1590!?

levacccp [35]

To solve this all you need to do is do the opposite of multipulcation:

1590/5

Which equal 318. To check you answer do 318×5

4 0

2 years ago

Read 2 more answers

X^2 + __x + 49 pls i need help<br><br> and i need 4x^2-24x+__

nadezda [96]

Answer:

4x2−24x4x2-24x

Factor 4x4x out of 4x24x2.

4x(x)−24x4x(x)-24x

Factor 4x4x out of −24x-24x.

4x(x)+4x(−6)4x(x)+4x(-6)

Factor 4x4x out of 4x(x)+4x(−6)4x(x)+4x(-6).

4x(x−6)4x(x-6)

4x2−24x4x2-24x

Step-by-step explanation:

tried

4 0

2 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$