Question

What is the volume of the oblique cylinder rounded to the nearest cm^3?

Answer 1

Answer: $32009355.90cm^3$

Step-by-step explanation:

Formula: $V=Bh$

Since the base is a circumference, we can replace B for the area of a circumference formula.

$V=\pi r^2h$

What we have here is 12 ft as the diameter of the circumference. A diameter is twice the radius, therefore we can conclude that if we take the diameter and divide it by 2, it will give us the radius.

$12/2=6ft$ this is the radius.

Now plug all this information into your formula.

$V=(3.14)(6ft)^2(10ft)\\V=(3.14)(36ft^2)(10ft)\\V=1130.40ft^3$

Our values are in feet but the question requires cm. Let's convert from $ft^3$ to $cm^3$.

Normally, our conversion factors are raised to the power of 1, but in this case it's raised to the power of 3. So, first let's see how many cm are 1 ft.

$1ft=30.48cm$

Here is where magic comes. We can raise both to the power of 3, in order to find the cubic ft and cm that we need as our conversion factors.

$(1ft)^3=(30.48cm)^3\\1ft^3=28316.8cm^3$

Now we have our conversion factors.

$1130.40ft^3(\frac{28316.84cm^3}{1ft^3})=32009355.90cm^3$