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kumpel [21]
3 years ago
9

ex-formula">÷2=18 what is x?
Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
I really don't know that looks super hard though
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Write an inequality to represent the phrase: The sum of a number an 6 is no less than 31
Leviafan [203]
The inequality that represents this phrase is n+6 > 31.
5 0
3 years ago
A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 ​respon
Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14​% chose chocolate​ pie, and the margin of error was given as plus or minus ±3 percentage points. 

The pivotal quantity for the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who chose chocolate​ pie = 14%

            n = sample of adults = 500

            p = true proportion

Now, the 99% confidence interval for p =  \hat p \pm Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.03 for 99% interval.

<u>So, 99% confidence interval for p</u>  =  0.14 \pm2.5758  \times \sqrt{\frac{0.14(1-0.14)}{500} }

                                                        = [0.14 - 0.03 , 0.14 + 0.03]

                                                        = [0.11 , 0.17]

Similarly, <u>80% confidence interval for p</u>  =  0.14 \pm 1.2816  \times \sqrt{\frac{0.14(1-0.14)}{500} }

Here, \alpha = 20% so  (\frac{\alpha}{2}) = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.02 for 80% interval.

So, <u>80% confidence interval for p</u>  =  [0.14 - 0.02 , 0.14 + 0.02]

                                                           =  [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0
4 years ago
From the set {80, 19, 11}, use substitution to determine which value of x makes the equation true. 8x = 88 A. none of these B. 1
mel-nik [20]

Answer:

  C.  11

Step-by-step explanation:

Substituting, we have ...

  8{80, 19, 11} ?= 88

  {640, 152, 88} ?= 88

The value from the set that makes the equation true is x = 11.

_____

<em>Alternate methods of solution (other than substitution)</em>

It can be easier to make use of your knowledge of factoring:

  8x = 8·11

  x = 11

Or to make use of your knowledge of numbers (place value):

  8·10 = 80

so x will not be very different from 10.

3 0
3 years ago
If y varies directly as x, and x = 48 when y = 6, find y<br> when x = 12.
pentagon [3]

Answer: Each time the pentagon is rotated , it maps back onto itself. There are five values of  for which the pentagon maps back onto itself. This is the same as the number of sides of the pentagon.

6 0
3 years ago
Read 2 more answers
A researcher claims that the average annual salary of part-time community college instructors is at least $45,000. To test this
Doss [256]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The researcher claims :

" the average annual salary of part-time community college instructors is at least $45,000 "

- We will extract the claim made by the researcher to be the Null hypothesis:

                     Null Hypothesis : μ ≥ $45,000

- Any statement otherwise, or point of rejection criteria will denote the Alternate hypothesis that disbands the claim that:

" the average annual salary of part-time community college instructors is less than $45,000 " :

                    Alternate Hypothesis : μ < $45,000

- This type of test with a sample size of n = 25 < 30 and population standard deviation is also not given hints the use t-test statistics and t-critical value reject the claim.

                     Lower tail - one sample - T-test.

6 0
3 years ago
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