We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
Step-by-step explanation:
<u>Step 1: Multiply inside the parenthesis
</u>
<u>Step 2: Multiply
</u>
<u />
Answer:
For 6 points, answering 5 questions is a rip-off.
However, I shall answer 7.
haha sike get noob
The number of participants with laptop is 115 and without laptop is 161
<u>Step-by-step explanation:</u>
Total number of participants= 276
Participants with laptop = (5/12) 276
= 115
Participants without laptop= 276 - 115
= 161
