To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
They need to be number C plus 3-2:7
<span>The slope of a line is -3
</span><span>perpendicular lines, slope is opposite and reciprocal
so </span><span>the slope of a line that is perpendicular to this line will be 1/3
answer
</span><span>C.1/3</span>
