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Naddik [55]
2 years ago
13

Need help finding intervals where the function is decreasing.

Mathematics
1 answer:
umka21 [38]2 years ago
8 0

f(x)=-5x-5\sin x\implies f'(x)=-5-5\cos x

f is decreasing on some interval (a,b) if f'(x) for all x\in(a,b). Similarly, f is increasing on (a,b) if f'(x)>0 for all x\in(a,b).

On the domain 0\le x\le2\pi, we have

-5-5\cos x=0\implies\cos x=-1\implies x=\pi

as the only critical point. So we need to check the sign of f' on two intervals, (0,\pi) and (\pi,2\pi).

On (0,\pi), pick any test value. Suppose we take x=\dfrac\pi2. Then f'\left(\dfrac\pi2\right)=-5, so f is decreasing on this interval.

On (\pi,2\pi), you'd find that f'>0, so f is increasing on this interval.

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5 0
3 years ago
a picture frame originally priced at $13.00 is on sale for $7.50. what is the percent of decrease, rounded to the nearest whole
faltersainse [42]
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8 0
2 years ago
0.04 is 1/10 of what number
bulgar [2K]
If you would like to calculate 1/10 of what number is 0.04, you can do this using the following steps:

1/10 of what number is 0.04
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x = 0.04 * 10
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Result: 1/10 of 0.4 is 0.04.
5 0
3 years ago
How do you solve this?
Katarina [22]

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Check the picture below.

6 0
3 years ago
Read 2 more answers
A group of fitness club members lose a combined total of 28 kg in one week there approximately 2.2 pounds and 1 kg assuming the
Akimi4 [234]

Answer:

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Step-by-step explanation:

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