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Vitek1552 [10]
3 years ago
5

A floorplan of a house is drawn to a scale of 1 inch:5 feet. The actual dimensions of the family room are 20 feet by 24 feet. Wh

at are the dimensions of the family room on the floorplan
Mathematics
1 answer:
expeople1 [14]3 years ago
8 0
Well every 5 feet will be drawn an inch in the floor-plan.

And given dimensions in feet must be multiplied by 1 inch/5 feet.

The dimensions are 4 inch by 4.8 inch.

Hope this helps you! (:
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Genrish500 [490]

Answer: -7

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What is the y-coordinate of the solution of the system of equations? {y=3x−262x−y=19
givi [52]

Answer:

<h2>           y = -5</h2>

Step-by-step explanation:

y = 3x − 26

2x − y = 19

2x - (3x - 26) = 19

2x - 3x + 26 = 19

   - x = - 7

     x = 7

y = 3•7 -26 = 21 - 26 = - 5

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It cost mrs sapranaro $245 for her and 6 people to take a day long guided tour of the Everglades how much does the guided tour c
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Read 2 more answers
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(calls last between 4.7 and 5.5 minutes)

P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z

P(4.7 \leq x \leq 5.5) = 44.52\%

b) P(calls last more than 5.5 minutes)

P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)

Calculating the value from the standard normal table we have,

1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%

c) P( calls last between 5.5 and 6 minutes)

P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z

P(5.5 \leq x \leq 6) = 5.01\%

d) P( calls last between 4 and 6 minutes)

P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z

P(4 \leq x \leq 6) = 91.45\%

e) We have to find the value of x such that the probability is 0.03.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03  

=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997  

Calculation the value from standard normal z table, we have,  

P(z < 2.75) = 0.997

\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08  

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0
3 years ago
The larger leg of a right triangle is 3 cm longer than its smaller leg. The hypotenuss is 6cm longer than the smaller leg. How m
xxTIMURxx [149]
Impossible to find out; no values were given.
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