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3 years ago

5

In an experiment the colours of 50 cars passing were recorded. 17 silver cars were recorded. What is the relative frequency of a

silver car passing?

2 answers:

Readme [11.4K]3 years ago

7 0

That out 50 cars there would be on average 17 of them silver or 17/50

Lina20 [59]3 years ago

3 0

17/50 would be your anwser

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What is the volume of a cylinder, in cubic centimeters, with a height of 8 centimeters

Arisa [49]

Answer:

1608.5 cm³

Step-by-step explanation:

Use the cylinder volume formula, V = $\pi$ r²h

If the diameter is 16 cm, then the radius is 8 cm.

Plug in the radius and height into the formula, and solve:

V = $\pi$ r²h

V = $\pi$ (8)²(8)

V = $\pi$ (64)(8)

V = 1608.5

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3 years ago

Please help, with factoring

lora16 [44]

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3 years ago

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Prove that root 7 is irrational by the method of contradiction

Alchen [17]

Let assume that $\sqrt7$ is a rational number. Therefore it can be expressed as a fraction $\dfrac{a}{b}$ where $a,b\in\mathbb{Z}$ and $\text{gcd}(a,b)=1$ .

$\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2$

This means that $a^2$ is divisible by 7, and therefore also $a$ is divisible by 7.

So, $a=7k$ where $k\in\mathbb{Z}$

$(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2$

Analogically to $a^2=7b^2$ ------- $b^2$ is divisible by 7 and therefore so is $b$ .

But if both numbers $a$ and $b$ are divisible by 7, then $\text{gcd}(a,b)=7$ which contradicts our earlier assumption that $\text{gcd}(a,b)=1$ .

Therefore $\sqrt7$ is an irrational number.

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4 years ago

tell whether the quotient is greater than or less than the dividend when you divide a whole number by a fraction . explain your

Fittoniya [83]

The quotient may be greater than or less than the dividend or divisor.
When the dividend is less than the divisor, the quotient will be less than one.
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4 years ago

Rearrange the quadratic equation so that it is equal to 0 then factor the equation x^2-4x=-2x+24

stealth61 [152]

$x^2-4x=-2x+24 \\
x^2-4x+2x-24=0 \\
x^2-2x-24=0 \\
x^2-6x+4x-24=0 \\
x(x-6)+4(x-6)=0 \\
\boxed{(x+4)(x-6)=0} \hbox{ - factored equation} \\
(x+4)(x-6)=0 \\
x+4=0 \ \lor \ x-6=0 \\
x=-4 \ \lor \ x=6 \\
x=-4 \hbox{ or } x=6
$

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4 years ago