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Morgarella [4.7K]
3 years ago
7

During a test, it is generally best to: A. answer all questions in order B answer the essay questions first C. answer the least

challenging questions first D answer the most challenging questions first
Computers and Technology
2 answers:
Alecsey [184]3 years ago
5 0

C. answer the least challenging questions first

because then you get those out of the way and have more time to focus on the harder questions.

Sedaia [141]3 years ago
4 0

Answer:

C.

Explanation: You want to take on the "not so hard ones" because your going easy first, You go from easy to medium to hard. Kinda like a game, You get different choices, You can choose easy, medium, hard , pro expret. It's better to do the challenging one's first because when your doing the easy one's first, your learning along the way and all your learning will help you with the tough questions

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Return the "centered" average of an array of ints, which we'll say is the mean average of the values, except ignoring the larges
denpristay [2]

Answer:

The code to this question can be defined as follows:

public double centeredAverage(ArrayList<Integer> nums) //defining a method centeredAverage that accepts an array nums

{

   if ((nums == null) || (nums.size() < 3))//define if block for check simple case value

   {

       return 0.0;//return float value

   }

   double sum = 0; //defining a double variable sum

   int smallest = nums.get(0);//defining integer variable and assign value

   int largest = nums.get(0);//defining integer variable and assign value

   for (int i = 0; i < nums.size(); i++) //defining for loop for stor ith value

   {

       int value = nums.get(i);//defining integer value variable to hold nums value

       sum = sum + value;//use sum variable for add value

       if (value < smallest)//defining if block to check value less then smallest

           smallest = value;//hold value in smallest variable  

       else if (value > largest)//defining else if block that checks value greater them largest value

           largest = value; //hold value in largest variable

   }

   sum = sum - largest - smallest;  // use sum to decrease the sum largest & smallest value

   return (sum / (nums.size() - 2)); //use return keyword for return average value

}

Explanation:

In the question, data is missing, that's why the full question is defined in the attached file please find it.

In the given code a method "centeredAverage" is used that accepts an array in its parameter and inside the method, if block is used that checks the cash value if it is true, it will return a float value.

In the next step, two integers and one double variable is defined, that use the conditional statement for check hold value in its variable and at the last use return keyword for return average value.

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Answer:

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the_____ tool is used to change the select text to capital letters or small letters (change case /grow font)​
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Answer:

on word you can use shortcut "Shift+f3" to change uppercase lowercase and title case if that is what you are asking for

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