He should purchase a Desktop PC as it would allow him to install high-power parts such as RAM, Graphics Card and CPU.
Answer:
def power(base, expo):
if expo == 0:
return 1
else:
return base * power(base, expo-1)
Explanation:
*The code is in Python.
Create a method called power that takes base and expo as parameters
Check if the expo is equal to 0. If it is return 1 (This is our base case for the method, where it stops. This way our method will call itself "expo" times). If expo is not 0, return base * power(base, expo-1). (Call the method itself, decrease the expo by 1 in each call and multiply the base)
Answer:
1. I express myself through the designing, development and analysis of software and hardware used to solve problems in a variety of business, scientific and social contexts.
2. support the development of general reasoning, problem-solving and communication skills.
3. Through avoiding in repetious tasks and simplifying such works.
Answer:
The most appropriate way to deal with the situation presented above is to acquire more space at the current office site at additional rent beforehand.
Explanation:
The Scaling of a revenue-generating business is a crucial task in which a lot of pre-planning and thinking is required.
In order to scale the business in the next year, the planning of it is to be carried out at the moment and proper necessary arrangements are ensured. These steps could be one from:
- Looking for bigger spaces for renting for a full shift of the operations
- Looking for a site office for an additional office
- Acquiring more space in the current office site.
This process would result in acquiring a bigger place beforehand but in order to mitigate the risk, try to keep the place in view by providing them a bare minimum advance for the additional units.
Answer:
void printC()
{
int i, j;
for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows
{
printf("C"); //print C for every row
for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows
{
if (i == 0 || i == 4) //For first and last row
printf("C"); //print 'CCCCCCC'
else if (i = 1|| i= 3) //for Second forth row
printf("C + +"); //print 'C + +'
else if (i = 2) For second row
printf("C +++++"); //print 'C +++++'
else
continue; //to jump to next iteration
}
printf("\n"); // print in next line
}
}
