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Andru [333]
3 years ago
15

a. Write a function called fizzbuzz. This function will take 1 number as a parameter. The function will print all numbers from 0

up to the number input (non-inclusive), but, if the number is divisible by 2 you will print fizz instead, and if the number is divisible by 3 you will print buzz instead. If it is divisible by both you will print fizzbuzz

Computers and Technology
1 answer:
OLga [1]3 years ago
5 0

Answer:

def fizzbuzz (num):

 for item in range(num):

   if item % 2 == 0 and item % 3 == 0:

     print("fizzbuzz")

   elif item % 3 == 0:

     print("buzz")

   elif item % 2 == 0:

     print("fizz")  

   else:

     print (item)

fizzbuzz(20)

Explanation:

Using Python programming Language

Use a for  loop to iterate from 0 up to the number using the range function

Within the for loop use the modulo (%) operator to determine divisibility by 2 and 3 and print the required output

see attached program output screen.

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In an office there is a unisex bathroom with n toilets. The bathroom is open to both men and women, but it cannot be used by men
Gnesinka [82]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <stdlib.h>

#include <pthread.h>

#include <semaphore.h>

int mcount,wcount;

sem_t x,y,z,wsem,msem,cap;

void delay(void)

{

int i;

int delaytime;

delaytime = random();

for (i = 0; i<delaytime; i++);

}

void *woman(void *param)

{

sem_wait(&z);

sem_wait(&wsem);

sem_wait(&y);

wcount++;

if(wcount==1)

{ sem_wait(&msem); }

sem_post(&y);

sem_post(&wsem);

sem_post(&z);

sem_wait(&cap);

printf("woman in!\n");

delay();

printf("\twoman out!\n");

sem_post(&cap);  

sem_wait(&y);

wcount--;

if(wcount==0)

{ sem_post(&msem); }

sem_post(&y);

}

void *man(void *param)

{  

sem_wait(&z);

sem_wait(&msem);

sem_wait(&x);

mcount++;

if(mcount==1)

{ sem_wait(&wsem); }

sem_post(&x);

sem_post(&msem);

sem_post(&z);

sem_wait(&cap);

printf("\t\tman in!\n");

delay();

printf("\t\t\tman out!\n");

sem_post(&cap);

sem_wait(&x);

mcount--;

if(mcount==0)

{sem_post(&wsem);}

sem_post(&x);

}

int main(void)

{

int i;

srandom(60);

mcount = 0;

wcount = 0;

sem_init(&x,0,1); // for sem_init, initial value is 3rd argument

sem_init(&y,0,1);

sem_init(&z,0,1);

sem_init(&wsem,0,1);

sem_init(&msem,0,1);

sem_init(&cap,0,4); // eg. cap initialized to 4

pthread_t *tid;

tid = malloc(80*sizeof(pthread_t));

// You can use your cobegin statement here, instead of pthread_create()  

// I have forgone the use of pthread barriers although I suppose they would nicely imitate the functionality of cobegin.

// This is merely to retain simplicity.

for(i=0;i<10;i++)

{

pthread_create(&tid[i],NULL,woman,NULL);

}

for(i=10;i<20;i++)

{  

pthread_create(&tid[i],NULL,man,NULL);

}

for(i=0;i<20;i++)

{  

pthread_join(tid[i],NULL);

}

return(0);

}

5 0
3 years ago
This program will convert a set of temperatures from Fahrenheit to Celsius and Kelvin. Your program will be reading in three dou
Naily [24]

Answer:

see explaination

Explanation:

#include<iostream>

#include<iomanip>

using namespace std;

int main()

{

double temp1,temp2,inc,cel;

int i=1;

while(i==1)

{

i=0;

cin>>temp1>>temp2>>inc;

if(temp2<temp1||inc<=0)

{

i=1;

cout<<"Starting temperature must be <= ending temperature and increment must be >0.0\n";

}

}

cout<<endl;

cout<<setw(15)<<"Fahrenheit"<<setw(15)<<"Celsius";

while(temp1<=temp2)

{

cel=(temp1-32)/1.8;

cout<<endl;

cout<<fixed<<setprecision(3)<<setw(15)<<temp1<<setw(15)<<cel;

temp1+=inc;

}

}

Please kindly check attachment for output.

8 0
3 years ago
He made me so angry when he didn’t let me make my point that I had to stalk after him.
madam [21]

Answer:

21

Explanation:

because

4 0
3 years ago
Read 2 more answers
Write a program with a function that accepts a string as an argument and returns the number of uppercase, lowercase, vowel, cons
diamong [38]

Answer:

Explanation:

The following code is written in Python. It is a function called checkString that takes in a string as an argument and loops through each char in that string and checking to see if it is lowercase, uppercase, vowel, consonant, or punctuations. It adds 1 to the correct variable. At the end of the loop it prints out all of the variables. The picture below shows a test output with the string "Brainly, Question."

def checkString(word):

   uppercase = 0

   lowercase = 0

   vowel = 0

   consonants = 0

   punctuation = 0

   vowelArray = ['a', 'e', 'i', 'o','u', 'y' ]

   consonantArray = ['b', 'c', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'm', 'n', 'p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z']

   punctuationArray = ['.', '!', '?', ',', ';', '(', ')']

   for char in word:

       if char.isupper():

           uppercase += 1

       else:

           lowercase += 1

       if char.lower() in vowelArray:

           vowel += 1

       elif char.lower() in consonantArray:

           consonants += 1

       if char in punctuationArray:

           punctuation += 1

   print('Uppercase: ' + str(uppercase))

   print('Lowercase: ' + str(lowercase))

   print('Vowels: ' + str(vowel))

   print('Consonants: ' + str(consonants))

   print('Punctuations: ' + str(punctuation))

8 0
3 years ago
What type of hacker is primarily motivated by an ideology, epitomizing "the ends justify the means" mentality?.
Hunter-Best [27]

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism.

<h3>What type of hackers are motivated by social or political issues?</h3>

Hacktivism is known to be an act of the wrong use a computer system or network for a socially or politically motivated  aim or reason.

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism and they are called hacktivist.

Learn more about Hacktivism from

brainly.com/question/5483494

#SPJ1

5 0
2 years ago
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